105 but I need 20 characters to
Hey!
First, let's write the problem,

Factor out the common term, which is 4,

Then, let's factor this part:

We are going to factor it using the difference of squares rule.

Our final factored answer would be,

Thanks!
-TetraFish
<h2>
Answer:37 paintings of $50 and 15 paintings of $75</h2>
Step-by-step explanation:
Let
be the number of paintings Ella sells for $
.
Let
be the number of paintings Ella sells for $
.
Profit made through $
paintings is 
Profit made through $
paintings is 
So,total profit is given by 
It is given that total profit is $
So,
..(i)
Given that the total number of prints is 
So,
..(ii)
using (i) and (ii),


The complete question is as follows.
The equation a =
can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths,
and
. Which are equivalent equations?
(a) 
(b) 
(c)
= 
(d) 
(e)
= h
Answer: (a)
; (d)
;
Step-by-step explanation: To determine
:
a = 
2a = (
)h


To determine h:
a = 
2a = 
= h
To determine 
a = 
2a = 


Checking the alternatives, you have that
and
= h, so alternatives <u>A</u> and <u>D</u> are correct.