EZ!
Let's say each box costs $X and each program costs $Y
Thus, Mike's family spent:
$(5X+3Y)
or
$41
Sean's family spent
$(3X+2Y)
or
$26
This yields us a system of two equations:
5x+3y=41
3x+2y=26
<span>5x+3y=41
</span>2y=26-3x
<span>5x+3y=41
</span><span>y=13-1.5x
</span>
5x+3(13-1.5x)=41
y=13-1.5x
5x+39-4.5x=41
<span>y=13-1.5x
</span>
0.5x+39=41
<span>y=13-1.5x
</span>
0.5x=2
<span>y=13-1.5x
</span>
x=4
<span>y=13-1.5x
</span>
x=4
<span>y=7
</span>
Each box costs $4 and each program costs $7
Answer:
⇒
2
√
3
(
1
+
√
2
)
−
√
2
+
3
√
5
Explanation:
(
2
√
3
+
3
√
20
−
(
4
√
2
−
3√
5
2
6
)
⇒
2
√
3
+
3
√
2−
4
√
2
+
3
√
5
+
2
√
6
,
Removing bracess
⇒
2
√
3
−
√
2
+
3
√
5
+
2
√
2
⋅
√
3
⇒
(
2
√
3
+
√
2
⋅
2
√
3
)
−
√
2
+
3
√
5 ⇒
2
√
3
(
1
+
√
2
)
−
√
2
+
3
√
5
