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pantera1 [17]
3 years ago
7

Please help fast and i brainliest!!! What is the first step in solving the equation 3x2−6x+1=0 by completing the square? Write t

he equation in standard form. Factor both sides of the equation. Write the equation in the form ax2+bx=c. If a≠1, divide each term by a. Use the square root property.
Mathematics
1 answer:
sashaice [31]3 years ago
8 0

Answer:

yoi look for what you add to the equation to make it a perfect square by dividing 6 by 2 then add 2^2 to both sides.

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Joe brought g gasoline for 2.75 per gallon and c cans of oil for 3.35 per can.
KatRina [158]

Answer:

Step-by-step explanation:

Let T represent the total amount spent.

The word and implies addition so the equation would be T= 2.75g+3.35c .

Now plug in the g and c values given in part b

So T= 2.75(5.8)+3.35(6)

Next simplify the expression

This is what T or the total Spent equals

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3 years ago
What is the expression below?<br> 26 + 67 + 3x2³
Alenkasestr [34]

Answer:

24x+93

That's the answer to the equation that was what you were asking for right?

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3 years ago
What is refraction of light​
USPshnik [31]

Answer:

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8 0
3 years ago
In circle o, the length of radius OL is 6 cm and the length
AlekseyPX

Answer:

14.2cm

Step-by-step explanation:

The diagram representing the circle and its attributes has been attached to this response.

<em>As shown in the diagram;</em>

The circle is centered at o,

The length of radius OL = 6cm

The length of the arc LM = 6.3cm

The angle MON = 75°

The angle LOM = θ

<em>Remember that;</em>

The length, L, of an arc is given by;

L = (θ / 360) x (2πr)         -------------(i)

Where;

θ is the angle subtended by the arc

r = radius of the circle.

Using the formula in equation (i), let's calculate the angle θ subtended by arc LM as follows;

L = (θ / 360) x (2πr)  

Where;

L = length of arc LM = 6.3cm

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation to get;</em>

6.3 = (θ / 360) x (2 x π x 6)

6.3 = (θ / 360) x (12 x π)

6.3 = (θ / 30) x (π)              [Take π = 22/7]

6.3 = (θ / 30) x (22 / 7)

θ = \frac{6.3*30*7}{22}

θ = 60.14°

Therefore, the angle subtended by arc LM is 60.14°

Now, from the diagram,

The angle subtended by arc LMN is;

θ + 75° = 60.14° + 75° =  135.14°

Let's now calculate the length of arc LMN using the same equation (i)

L = (θ / 360) x (2πr)  

Where;

L = length of arc LMN

θ = angle subtended by LMN = 135.14°

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation;</em>

L = (135.14° / 360°) x (2 x π x 6)             [Take π = 22/7]

L = 14.15cm

Therefore, the length of arc LMN is 14.2cm to the nearest tenth.

6 0
3 years ago
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