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dybincka [34]
3 years ago
7

Write a real-world word problem that can be solved using elapsed time. Include the solution.

Mathematics
1 answer:
ElenaW [278]3 years ago
3 0
Or...you could do this.

Lacey walks in a store at 8:30,the store opens at 12:00,how much time does Lacey have to get the store opened and stock the shelves?

4 1/2hours
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Log(x)²=(logx)², find the value of x​
Gnesinka [82]

Answer:

x = 7.39

Step-by-step explanation:

log(x)²=(logx)², find the value of x​

log x² = log x * log x

2log x = log x * log x

2 = log x

Take the exponent pf both sides

e² = e^logx

e²  = x

x  = e²

x = 7.39

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3 years ago
HELPPPP PLS!! TY
Leya [2.2K]

Answer:

B at ordered pair 1, 2, hope this helped

Step-by-step explanation:

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2 years ago
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The equation y=20646 x 0.86^x estimates the value of a brand of car x years after it was purchased new. milo purchased this bran
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20646(.86^11) = 3929
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3 years ago
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The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
Which of the following equations is not a linear equation? a. y = x + 6 b. y2 = x2 + 3 c. x = 5 d. 2x = 3y
vaieri [72.5K]
<h3>Of the four listed equations, B is the only equation that is not linear.</h3>

A linear equation is any equation that results in a straight line, as each value is a fixed number from the previous.

In a non-linear equation, a variable is being raised to a power, which results in a curved line.

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3 years ago
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