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3 years ago

What is the area of a regular hexagon with a side length of 12 cm?

Mathematics

1 answer:

ddd [48]3 years ago

4 0

Area = 374.12 cm2 , That last 2 after cm is the small up 2 but I can't make symbol on my keyboard

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3 years ago

Find each measurement indicated. Round your answers to the nearest tenth.

Crazy boy [7]

Answer:

Step-by-step explanation:

Find AB using the Law of Sine:

$\frac{AB}{sin(C)} = \frac{AC}{sin(B)}$

Thus:

$\frac{AB}{sin(40)} = \frac{47}{sin(103)}$

Multiply both sides by sin(40)

$\frac{AB}{sin(40)}*sin(40) = \frac{47}{sin(103)}*sin(40)$

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3 years ago

Frank’s family is going on vacation. Their trip is a total of 465.8 miles. On Monday they drive 157.4 miles, and on Tuesday they

statuscvo [17]

Answer:

118.8

Step-by-step explanation:

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3 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

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THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

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3 years ago