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dimaraw [331]
3 years ago
9

Imagine we are throwing a five-sided die 50 times. On average, out of these 50 throws, how many times would this five-sided die

show an odd number? (1 & 3 & 5)
___ out of 50 throws
Mathematics
2 answers:
Studentka2010 [4]3 years ago
7 0
Try putting the 3/5 which creates a fraction which you can times by 50

3 is how many odd number there are and 5 is how many overall numbers you have, this will create a decimal or fraction that you can times by 50 to get the Answer.
This process generally works for just about any of these questions
olganol [36]3 years ago
4 0
16.6 times because if there is 3 numbers you simply divide it into 50
You might be interested in
What is the angle in a triangle that is part of a linear pair? i will give 15 points im desperate
gogolik [260]

Answer:  Linear pairs of angles add up to 180 degrees. A+B=180

Step-by-step explanation: A linear pair of angles is formed when two lines intersect. Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees

7 0
3 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST !!
AveGali [126]

Answer:

Angles and XWY and STR

Step-by-step explanation:

These two angels are alternate exterior angels because:

- They are on different sides of the transversal (the line intersecting the two parallel lines)

- They have the same angle measure

- They are exterior, meaning they are on the outside, not inside (interior)

Hope this helps!!! :)

8 0
3 years ago
Find the remainder when f(x)=−2x3+x2−4x+1 is divided by x+3.
andre [41]

Answer:

4 the answer is 4

Step by step explanatin:

8 0
2 years ago
PLEASE HELP I WILL PICK BRAINLIEST
Mnenie [13.5K]

Answer:

A more complex question has rarely been asked.

Principia Mathematica took nearly a thousand pages to prove that 1+1=2. It does meander a bit, but had they wanted to prove 1+1=2 alone, it could have done so in 500 pages.

Mathematically speaking, the definition of 1 is:

There exists a number such that when multiplied upon an element of a specified set, yields the element of the specified set.

It is also defined as:

1.0000000000000000000000…

.9999999999999999999999999…

as the set of all singletons.

a singleton is a set with exactly 1 element.

These 4 definitions work in tandem with one another.

For example:

1=1

Divide both sides by 3.

1/3=1/3

Rewrite.

1/3=.33333333333333333...

Multiply both sides by 3.

1=.9999999999999999999...

Similarly:

If    =.9999999999999999999...

10=9.99999999999999999...

10=9+.99999999999999...

10=9+

Simplify by subtracting x from both sides.

9=9

=1

.99999999999999999999...=1

As the set of all singletons, 1 is also THE element that represents the set of all single entities.

That is to say: if you have 7 erasers. What you really have is a set of 7 single entities. The definition of 7 becomes: 1 + 1 + 1 + 1 + 1 + 1 + 1; and not as is commonly believed as: 6 + 1.

There is an argument for 7 to be defined as 6 + 1, but this argument is a corollary of the Peano Axioms which in turn argues that there exists a set with absolutely nothing in it {} and a set with exactly something in it {x}. More on this later.

The Principia Mathematica uses Peano's (from the Peano Axioms mentioned earlier) work and notation to expertly slice through the many nuances pertaining to this question.

This is something we will not do; but hopefully, we will also be able to effectively demonstrate why 1 + 1 = 2 in less than 1000 pages.

We will assume these basic principles of number theory:

There exists a number such that when multiplied to an element of a specific set, yields that element of the specific set.

There exists a number such that when added to an element of a specific set, yields that element of the specific set.

If we again assume to have only two sets, a set that is empty: {} containing no elements, and a set that is not empty {x} containing an element. We realize that Consequently, we went from nothing {}, to something {x}. This means that {x} is the successor to {}, as the next step up from nothing, is something.

As such we now have two elements:

Nothing, {}, and something that comes after {}, this something is called the successor, and it is the Successor of nothing.

in written notation we have:

{} and { the Successor of nothing }

Rewritten:

{0, the thing that comes after 0}

Further reworded:

{0, Successor (0) }

Reduced further:

0,(0)

Where S(0) stands in place of ‘the successor’. Further, we know there are an infinite number of possible Natural numbers, and we get:

{0, Successor of 0, the successor of the successor of 0, the successor of the successor of the successor of 0,…}

Further reduced:

0,(0),((0)),(((0))),((((0)))),(((((0)))),…

Further explained:

We know that we had nothing, and added something to it, and got something:

Nothing + Something = Successor of nothing.

0+__=(0)

We also know that there is nothing closer to 0, than the thing that comes after 0.

0+(0)=(0)

This implies that S(0) is the smallest increment possible from natural number to next natural number.

As a consequence, we now have two discovered entities: Something, and Nothing.

Let’s give them names.

We have decided that

Nothing = 0 .

0 = Nothing.

S(0) is the something that comes after nothing.

We define a new symbol: 1, to be: 1 = S(0)

This is to say that 1 IS the symbol that succeeds 0;

We could have drawn any shape to define the number that succeeds 0; we chose to draw a 1.

0+(0)=(0)

0+1=(0)

0+1=1

0,1,((0)),(((0))),((((0)))),(((((0)))),…

We now have definitions for 0, and 1. What about a definition for the thing that comes after one? The successor of 1?

As we know S(0) is the smallest increment available, and we are interested in finding S(0)’s successor we investigate:

The successor to the successor of Nothing:

0+(0)=1;1+(0)=(1)

This reads:

The successor of the successor of nothing IS the successor of one

And now… we need a new symbol.

We define the

(1)=2

The successor of 1 IS 2.

Thus:

0+(0)=1;1+(0)=(1)=2

Simplify:

0+1=1;1+1=(1);(1)=2.

Further:

0+1=1;1+1=2;2=2.

1 has many different properties; but all of the properties and their resulting definitions have little to do with why 1 + 1 = 2. And that 1 + 1 = 2 is a byproduct of properties inherent to Natural numbers.

Step-by-step explanation:

6 0
3 years ago
There are 25 students in Mrs. Venetozzi’s class at the beginning of the school year, and the average number of siblings for each
andrezito [222]
Adding the student with eight siblings will increase the class average amount of siblings because this student has more siblings than the average.

Therefore, the average number of siblings that each student has is larger than the original average.
7 0
3 years ago
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