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love history [14]
3 years ago
8

Solve the equation. (3b - 4)/5 = -b +4

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

b=3

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

b

=

3

b=3

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A building in a city has a rectangular base. the length of the base measures 65 ft less than twice the width. the perimeter of t
dybincka [34]

By solving a system of equations, we will see that the width is 170ft and the length 275 ft.

<h3>How to get the dimensions of the base?</h3>

For a rectangle of length x and width y, the perimeter is:

P = 2*(x + y).

Here we know that:

x = 2y - 65ft

p = 890ft = 2(x + y)

So we have a system of equations.

To solve this, we need to replace the first equation into the second one:

890ft = 2(x + y)

890ft = 2(( 2y - 65ft) + y)

Now we can solve this for y.

890ft = 4y - 130ft + 2y

890ft + 130ft = 6y

1020ft/6 = y = 170ft

So the width is 170ft, and we know that:

x = 2y - 65ft = 2*(170ft) - 65ft = 275ft

So the length is 275 ft.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

5 0
2 years ago
Arrange 31/40, 78%, 0.7 in ascending order
Setler [38]
It would be first 31/40,0.7,78%

It might be wrong

5 0
3 years ago
Read 2 more answers
The length of a rectangle is 6 meters more than its width. If the area is 135 square meters, what is its width?
Novay_Z [31]
Length = width +6

L * (L - 6) = 135

L^2 - 6L = 135

L^2 - 6L -135 = 0

Length = 15
Width = 9


4 0
3 years ago
Find (f•g)(2) given f(x)=x-3 and g(x)=x+3<br><br> Please show your work
marissa [1.9K]

Answer:

f.g(x) = f(g(x))\\f(g(2)) = ?\\\\g(x) = x+3 \\g(2) = 5\\\\f(x) = x-3\\f(g(2)) = f(5) = 2=f.g(2)

Step-by-step explanation:

7 0
2 years ago
Mrs. Bhatia's closet consists of two sections, each shaped like a rectangular prism. She plans to buy mothballs to keep the moth
AveGali [126]

Answer:

6.5 boxes

Step-by-step explanation:

Given

See attachment for closet

Required

Determine the number of boxes needed to fill the closet

First, we calculate the volume of the two section.

According to the attachment

The first section has the following dimension:

Width = 5ft

Length = 4ft

Height = 8ft

The second has the following dimension:

Width = 3ft ---- see the last label at the top

Length = 2ft --- This is calculated by subtracting the length of the first section (4ft) from the total length of the closet (6ft) i.e. 6ft - 4ft

Height = 8ft

So: The volume of the closet is:

Volume = W_1 * L_1 * H_1 + W_2 * L_2 * H_2

Volume = 5ft * 4ft * 8ft + 3ft * 2ft * 8ft

Volume = 160ft^3 + 48ft^3

Volume = 208ft^3

The number of box needed is then calculated by dividing the volume of the closet (208ft^3) by the volume of each box (32ft^3)

Boxes = \frac{208ft^3}{32ft^3}

Boxes= \frac{208}{32}

Boxes = 6.5

7 0
3 years ago
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