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Answer:
I think it 2 solution to the problem you can add or multiple
The total number of handshakes was 234.
- The first man shook hands with 12 other men.
- The second man shakes hands with 11 other men, as he had already shaken hands with the first man.
- Like-wise, the last man does not need to shake hands again as every man has already shaken hands with him in their respective turns.
- The number of handshakes among men is 0 + 1 + 2 + … + 12.
- The sum of "n" natural numbers = (n)(n+1)/2
- The number of handshakes among men is 12(13)/2.
- The number of handshakes among men is 78.
- Each man shakes hands with every woman except his spouse.
- Each man shakes hands with 12 other women.
- The number of handshakes between men and women is 13*12.
- The number of handshakes between men and women is 156.
- The total number of handshakes is 78 + 156.
- The total number of handshakes is 234.
To learn more about natural numbers, visit :
brainly.com/question/17429689
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Answer:
11 would be the answer!
Step-by-step explanation:
Evaluate the power
Calculate the sum
Hope this helps! :)
