What is the distance between the points (-1,-9) and (4,-2)?

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

Calculate dy/dx when xy^3 + y =3x

Brilliant_brown [7]

You have to use implicit derivative

dy / dx = y'

xy^3+y=3x

y^3 + 3xy^2 y' + y' = 3

[3xy^2 + 1) y'= 3 - y^3

          3 - y^3
y' = -----------------   <-----------answer
         3xy^2 + 1

6 0

2 years ago

How to convert y = - 2\5 x to standard form

coldgirl [10]

Bring it to the form ax + by = c, where a is positive, and there are no fractions in the equation.
Here, we need to add 2/5x to both sides:
2/5x + y = 0
Then multiply everything by 5 to get rid of the fraction
2x + 5y = 0 <==

5 0

2 years ago

According to a survey of 1000 families of any town in 2010 A.D.,794 families have radio and 187 families have television.lf 63 f

hjlf

Answer:

Number of families will have both radio and television = 44

Step-by-step explanation:

Given:

Number of family have radio = 794

Number of family have TV = 187

Number of family haven't both = 63

Find:

Number of families will have both radio and television

Computation:

Number of families will have Tv or radio = 1,000 - 63

Number of families will have Tv or radio = 937

Number of family have one of them = 794 + 187

Number of family have one of them = 981

Number of families will have both radio and television = 981 - 937

Number of families will have both radio and television = 44

4 0

2 years ago

Two nickels are flipped and a number cube is rolled. How many total outcomes are there?

Taya2010 [7]

Answer:

2

Step-by-step explanation:

3 0

2 years ago

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