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Levart [38]
2 years ago
8

What is the distance between the points (-1,-9) and (4,-2)?

Mathematics
1 answer:
Crank2 years ago
4 0

\sqrt{74}, or 8.60

Just use the distance formula

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Write as a decimal<br><img src="https://tex.z-dn.net/?f=1%20%5Ctimes%20%5Cfrac%7B5%7D%7B8%7D%20" id="TexFormula1" title="1 \time
Sever21 [200]

<em>Answer</em>

<u>0.625</u>

<em>Explanation</em>

5/8=0.625

1 x 0.625= 0.625

(basically the question was "convert 5/8 to a decimal" because 1 times any number is the same number)

<em>hope this helps!</em>

<em>have a great day :)</em>

5 0
3 years ago
Help please I will give brainleist
Natali5045456 [20]

Answer:

The answer is 80%

8 0
2 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Levart [38]

Answer:

"A ceiling fan"

Step-by-step explanation:

Cycles that may repeat or break.

5 0
2 years ago
write an equation to represent the relationship, and find the amount of peanut butter used to make 25 cracker packages. the tabl
Nadusha1986 [10]

We are given 4 points.

(\frac{1}{2},2)

(\frac{5}{8},\frac{5}{2})

(\frac{3}{4},3)

(\frac{7}{8},\frac{7}{2})

Using this, we can make an equation.

y=4x

I got m=4 by using the slope formula.

m=\frac{2.5-2}{0.625-0.5}

m=\frac{0.5}{0.125}

m=4

So the equation we have is y=4x

Now, we can solve for how much peanut butter is used to make 25 packages by plugging in 25 for y, which is the number of cracker packages.

25=4x

x=\frac{25}{4}

We need to use \frac{25}{4} teaspoons of peanut butter to make 25 packages of crackers.

Hope this helps.

頑張って!

4 0
3 years ago
Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

8 0
3 years ago
Read 2 more answers
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