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Pani-rosa [81]
3 years ago
13

Does anyone know the answer to this!?

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer:

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},

where

|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

So,

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

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The top number is your rise and your bottom number is your run and when you graph all the points on a graph the point that crosses the y-axis is your y-intecept.
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3 years ago
Read 2 more answers
Determine whether the lines are parallel, intersect, or coincide. x-5y=0, y+1=1/5(x+5)
MAXImum [283]

<u>Answer-</u>

<em>The lines are two </em><em>coinciding lines</em><em> or the </em><em>same lines</em><em>.</em>

<u>Solution-</u>

The given line equations are

the first one,

\Rightarrow x-5y=0  

the second one,

\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0

As we know two line equations A_1x+B_1y+C_1=0 and A_2x+B_2y+C_2=0 will be,

  1. Parallel if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}
  2. Coincide if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}
  3. Intersect if, \dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}

As here,

\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}

\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

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3 years ago
A triangle ABC is inscribed in the circle, (ABC = 65° and AB=AC. Find (BDC.
podryga [215]

Answer:

∠BDC=50°

Step-by-step explanation:

∠BDC=∠A[angles at the same segment)

∠A= 180-(65+65)=180-130= 50°

so, ∠BDC=50°

<em>MARK ME BRAINLIEST</em>

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6\9 to the simplest fraction is 2\3
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The length of a rectangle is the width minus five units.the area of the rectangle is 36 units.what is the width,in units,of the
Andreas93 [3]
Length × Width = Area

-5*Width = 36

Simply divide 36 by 5 to get your answer


Hope that helps!!!!
8 0
3 years ago
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