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Pani-rosa [81]
3 years ago
13

Does anyone know the answer to this!?

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer:

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},

where

|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

So,

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

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Answer:

(- 5, 1 )

Step-by-step explanation:

- 6x - 14y = 16 → (1)

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Multiplying (2) by - 3 and adding to (1) will eliminate the x- term

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Substituting into (1)

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