Ask question

Ask question

All categories

3 years ago

12

A car is towed using a force of 1600N. The rope used to pull the car makes an angle of 25∘ with the horizontal. Find the work do

ne in joules(1J=1N⋅m) in towing the car 2km. Round the answer to the nearest integer. Do not enter commas in your answer.

1 answer:

mezya [45]3 years ago

5 0

Answer: 2900185 Joules

Step-by-step explanation:

Force used to tow the car is 1600N

Angle(α)= 25

Displacement = 2km

Recall that 1km= 1000m

Therefore 2km= 2000m

Workdone= FdCos α

W= 1600 * 2000 * cos 25

W=2900184.919

W= 2900185 Nm(when approximated to the nearest integer)

Since 1J = 1Nm

Work done = 2900185 J

You might be interested in

What is 30% of a book with 210 pages

Masteriza [31]

Answer:

63 pages

Step-by-step explanation:

I AM NOT SURE THIS IS CORRECT. I WILL EXPLAIN MY REASONING THOUGH.

Take 210 (pages) and multiply that by 30% or 0.3 that will give you 63. This means that 30% of the book is 63 pages

7 0

3 years ago

Three consecutive even integers whose sum is -48

Salsk061 [2.6K]

Three consecutive even integers whose sum is -48

6 0

2 years ago

Below is a pair of vectors. add them and insert your answer here: ab+bc=(-3-1)+(-4 2)=<br>

jarptica [38.1K]

Answer:

(-7, 1)

Step-by-step explanation:

Add the x and y values separately which is across from your screen to get the function which is (-7, 1).

8 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

A patient drinks 5 12ounce cups of coffee daily. The doctor recommends cutting back 60%, how many ounces of coffee can the patie

maksim [4K]

The patient is recommended to take 24 ounces of coffee per day.

<u>Step-by-step explanation:</u>

Patient normal intake of coffee daily = 5 times 12 ounces

= 5 × 12 = 60 ounces

Doctor recommends to cut off 60 % of the normal intake of coffee.

And advised to take only 40 % of the daily intake of coffee.

So 60 % of 60 ounces can be calculated as,

$$\frac{60 \times 60}{100}$ = 36 ounces

40 % of 60 ounces is 24 ounces.

So 60 - 36 = 24 ounces of coffee per day

6 0

2 years ago