Answer:

Step-by-step explanation:
we know that
The area of a regular hexagon is the same that the area of 6 equilateral triangles
The area of 6 equilateral triangles applying the law of sines is equal to
![A=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
where
b is the length side of the regular hexagon
we have

substitute
![A=6[\frac{1}{2}(10)^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%5E2sin%2860%5Eo%29%5D)

2 (x - 5) = 8
To solve, you use the distributive property as shown below!! :)
2x - 10 = 8
2x = 18
x = 9
Hope this helped you :)
Answer:
ok ask the question plzzzzz
It’s b I think hope this helps you