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miss Akunina [59]
2 years ago
11

Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she u

sed 6.2 years as her time period
Explain how she would calculate the difference between how much water levels rose on average and how much the water level fell in the part of the river she observed.
Mathematics
1 answer:
olga nikolaevna [1]2 years ago
7 0

Answer:

Sample response:

Step-by-step explanation:

She would multiply the rate by the years to find the average rise in water levels, or 1.8 times 6.2 = 11.16. To find the difference between the water levels, she would subtract -13.64 from 11.16.

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Otrada [13]

Answer: 160 songs.

Step-by-step explanation:

<em>75% hip hop music   -    120 songs </em>

<em>100% all music          -     x songs </em>

<em>Let's write the proportion:</em>

<em />\dfrac{120}{75} =\dfrac{x}{100} \\\\75x=120 \cdot 100\\75x=12000\\75x : 75 = 12000 : 75\\x = 160<em />

<em>Thus, Landon have 160 songs in his music library.</em>

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3 years ago
The sum of four consecutive
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Answer:

42 is the smallest of the 4 numbers.

Step-by-step explanation:

The 4 consecutive integers that total 174 are 42,43,44, and 45. Therefore, 42 is the smallest out of all 4 integers.

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2 years ago
What are the next three terms of the following geometric sequence: 32, 48, 72...
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32

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48

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72

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Step-by-step explanation:

6 0
2 years ago
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Angle CDE has a slightly greater measure than the measure
svlad2 [7]

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6 0
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Find the oth term of the geometric sequence 5,--25, 125,
Genrish500 [490]

Given the geometric progression below

5,-25,125,\ldots

The nth term of a geometric progression is given below

T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}

From the geometric progression, we can deduce the following

\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}

To find the value of r, we will take ratios of two consecutive terms

\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}

To find the 9th term of the geometric, we will have that;

\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}

Hence, the 9th term of the geometric progression is 1953125

8 0
9 months ago
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