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miss Akunina [59]
3 years ago
11

Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she u

sed 6.2 years as her time period
Explain how she would calculate the difference between how much water levels rose on average and how much the water level fell in the part of the river she observed.
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

Sample response:

Step-by-step explanation:

She would multiply the rate by the years to find the average rise in water levels, or 1.8 times 6.2 = 11.16. To find the difference between the water levels, she would subtract -13.64 from 11.16.

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What is the approximate solution to this equation? x³ = 27.55
worty [1.4K]

Answer: 3

Explanation:

Since we’re finding a cube root, the closest cube root to 27.55 is 27. Since 3 cubed is 27, the cube root of 27.55 is about 3

6 0
3 years ago
William recorded data to determine the relationship between the time usage, x, and the percentage of charge left on his mobile p
mart [117]
The answer is B. In 10 hours, the phone would completely lose its charge.
Y=-10(10)+100=-100+100=0
8 0
4 years ago
Read 2 more answers
Howdy!
posledela

Answer:

A) Central angle has same measure as intercepted arc.

  • mCE = mCD + mDE = 20° + 90° = 110°

B) Opposite angles of cyclic quadrilateral are supplementary.

  • mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
  • m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
  • m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
  • mQP = 360° - (90° + 76° + 72°) = 122°

C)

  • m∠MLN = m∠MRN as same arc MN is intercepted
  • m∠LMN is right angle as opposite side is diameter.
  • ∠MNL is complementary with ∠MLN which is same as ∠MRN
  • m∠MNL = 90° - 47° = 43°

D) Tangent secant angle is half of the intercepted arc.

<em>It seems wrong. Should be mQP instead of mQR</em>

  • mQP = 2*m∠RQP = 2*74° = 148°
8 0
3 years ago
the alexander family and jenkins family each used their sprinklers last summer. the water output rate for the alexander familys
Mumz [18]

Answer:
Alexanders family sprinkler used for 35.25 hours
And the Jenkins family sprinkler was used for 29.75 hours.

Step-by-step explanation:

Lets start with 2 assumptions, what if we only used the Alexander's family sprinklers, We can define X as the variable
20x=1450
x= 72.5
If we just used the Alexanders it would of took 72 hours and 30 minutes.

Now lets look at the Jenkins family sprinkler, lets define it as Y.
25y=1450
y = 58
With only the Jenkins it would of took 58 hours.

Now, if they just of shared the work equally among the two sprinklers, the Alexanders family doing 725 L and the Jenkins with the other half.
It would of took the Alexanders
20x= 725
x=36.25

Jenkins
25y=725
y=29

Making it a combined time of 65.25 hours. 15 minutes long of our 65 hour time.

Now the Jenkins sprinkler generates 5 more L than Alexanders per hour. Which means it would only take the Jenkins family 1 hours to make 25 liters but Alexanders would take \frac{5}{4} hours. We know that 1 hour contains 60 minutes, which means \frac{1}{4} of a hour contains 15 minutes.

So it would take Alexanders family sprinkler 15 minutes more to produce the same amount per hour that the Jenkins does.

So from this we can conclude that if the Jenkins family sprinkler was used more we can cut the extra 15 minutes off, making the answer That the

Alexanders family sprinkler used for 35.25 hours
And the Jenkins family sprinkler was used for 29.75 hours.

7 0
2 years ago
A teacher gave a test with 50 questions, each worth the same number of points. Donovan got 38 out of 50 questions right. Marcis
melisa1 [442]

Answer:

38

Step-by-step explanation:

38of 502bhfghggiggjgfhhffj

8 0
3 years ago
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