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musickatia [10]
3 years ago
6

Which figure shows a reflection of pre-image ABC over the y-axis? Please help

Mathematics
2 answers:
elena-s [515]3 years ago
5 0

Answer:

C

Step-by-step explanation:

The pre-image is the starting image before the reflection. The reflection needs to be over the y-axis so, the third graph (C) would be correct.

bija089 [108]3 years ago
4 0

Answer:

The third one C)

Step-by-step explanation:

when you reflect over the y-axis you multiply the x-coordinates by -1

Hope that was helpful

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Pure copper was mixed with a 10% copper alloy to produce an alloy thát was 25% copper. How much of the pure copper and how much
lora16 [44]

Answer:

6kg pure copper and 30 kg 10% copper was mixed to give 36kg of 25% alloy

Step-by-step explanation:

Here, we want to produce 36 kg of 25% alloy

Let the Pure copper be x kg while 10% alloy be y kg

Pure copper is simply 100% copper

Thus;

x + y = 36 •••••(i)

Then;

100% of x + 10% of y = 25% of 36

= x + 0.1y = 9 •••••• ii)

From i x = 36-y

from ii, x = 9-0.1y

Equate both x

36-y = 9-0.1y

36-9 = 0.1y + y

0.9y = 27

y = 27/0.9

y = 30

x = 36-y

x = 36-30

x = 6 kg

8 0
3 years ago
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128 times 2 is 256 divided by 2 is 128 scoops of ice cream
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A line is drawn so that it passes through the point (3,4) and (2,1). what is the slope of the line
Tamiku [17]
Y2-y1/x2-x1
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7 0
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Analyze the diagram below and complete the instructions that follow.
Phantasy [73]

Answer:

Option (B)

Step-by-step explanation:

From the figure attached,

ΔBCD and ΔACE are the similar triangles.

Therefore, by the property of similar triangles, corresponding sides of these similar triangles will be proportional.

\frac{AC}{BC}= \frac{EC}{DC}

\frac{AB+BC}{BC}= \frac{ED+DC}{DC}

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Option (B) will be the answer.

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