She had 2.75 liquid gallons
Answer:
Part 1.
In 12 hours 30 units of Humulin R insulin in 300 mL is to be infused.
So, per hour = units are to be infused.
Part 2.
Now 30 units Humulin R insulin in 300 mL of normal saline (NS).
So, 2.5 units will be in : mL
Hence. 2.5 units Humulin R insulin in 25 mL of normal saline (NS).
Answer:
-10x + 38.
Step-by-step explanation:
-2(x - 3) + 4(-2x + 8)
= -2x + 6 - 8x + 32
= -10x + 38.