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Vadim26 [7]
3 years ago
14

What is the coefficient of q in the sum of these two expressions? (23q – 34) and (–16q – r) NEED HELPPP

Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

The coefficient of q is 7

Step-by-step explanation:

The two expressions are

23q-34 and -16q-r.


The sum of the two expressions is


23q-34+-16q-r


When we group like terms the expression will be,


=23q-16q-r-34


When we  simplify the expression will now be


=7q-r-34

The coefficient of q is the constant behind q in the expression.

The coefficient of q is  therefore 7.



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dem82 [27]
Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.

Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.


_____
In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
  R + J = total speed
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Adding these two equations, we have
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4 0
3 years ago
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

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3 years ago
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A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per in
TiliK225 [7]

Answer:

The population growth rate is <u>59</u> squirrels per year.

Step-by-step explanation:

Given:

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per individual per year and the population size is 275.

Now, to find the population growth rate.

Carrying capacity (K) = 350.

Maximum rate (r_{max}) = 1.0 per individual per year.

Population size (N) = 275.

Now, to get the population growth rate we put formula:

\frac{dN}{dT}= r_{max}\frac{K-N}{K}N

\frac{dN}{dT}=1.0\times \frac{350-275}{350}\times 275\\\\\frac{dN}{dT}=1.0\times \frac{75}{350}\times 275\\\\\frac{dN}{dT}=1.0\times 0.214\times 275\\\\\frac{dN}{dT}=58.85.

<u><em>So, rounding to nearest whole number of the population growth rate is 59 squirrels per year.</em></u>

Therefore, the population growth rate is 59 squirrels per year.

6 0
2 years ago
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