Two towns that are 330 km apart are three cm apart on a map. What is the scale of the map?

Mathematics

1 answer:

alexgriva [62]2 years ago

3 0

Answer:

1cm = 110km

Step-by-step explanation:

$\frac{3}{3} cm = \frac{330}{3} km \\ 1cm = 110km$

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Find the measure of the angle shown by the arrow(in radians)

soldi70 [24.7K]

Answer:

-7π/3 or -420 degrees

Step-by-step explanation:

So we know that the arrow has made one full rotation and that it is moving in a clockwise direction. So already we have -2π degrees.

The arrow stops at π/6 before the next π/2 rotation. Therefore we find the difference between the two.

π/2 - π/6

3π/6 - π/6 = 2π/6

π/3

Since this is still clockwise, we make this negative. So the measure of the angle shown by the arrow is -2π - π/3

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3 years ago

About 5 percent of tourists who go to Egypt visit the pyramids of Dahshur. Let's say that a group of 480 tourists goes to Egypt.

Leni [432]

Answer:

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Step-by-step explanation:

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2 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)