A^2 + b^2 = c^2
20^2 = 400
52^2 = 2704
400 + b^2 = 2704
2704 - 400 = 2304
So you need the square root of 2304 which is 48 so the length of the other leg is 48 ft.

8 0

3 years ago

Please help me thank you

Andreas93 [3]

Answer:

1.c

2.b

3.a

4.d

5.c

Step-by-step explanation:

please click the heart and rate excellent and brainleist to ☻❤☺️☺️❤☻

5 0

3 years ago

Solve the equation for x. 27(x - 108) = 54

Sidana [21]

X = 110

110-108 = 2

27*2=54

4 0

3 years ago

Read 2 more answers

Henry ran five races, each of which was a different positive integer number of

dolphi86 [110]

Answer:

10 miles.

Step-by-step explanation:

Let x be the number of miles on Henry's longest race.

We have been given that Henry ran five races, each of which was a different positive integer number of miles.

We can set an equation for the average of races as:

$\frac{\text{The sum distances of 5 races}}{5}=4$

As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.

Now let us substitute the distances of 5 races as:

$\frac{1+2+3+4+x}{5}=4$

$\frac{10+x}{5}=4$

Let us multiply both sides of our equation by 5.

$\frac{10+x}{5}*5=4*5$

$10+x=20$

Let us subtract 10 from both sides of our equation.

$10-10+x=20-10$

$x=10$

Therefore, the maximum possible distance of Henry's longest race is 10 miles.

7 0

3 years ago