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Brut [27]
3 years ago
10

The price of a candy bar is $1.53. If this is three cents more than triple the price ten years ago, how much did the candy bar c

ost ten years ago?
Mathematics
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

$0.51

Step-by-step explanation:

Hello! Using what we know, the price of the candy bar at the moment is $1.53, triple the price from 10 years ago. So, triple cents would technically be $0.03. We divide $1.53 and $0.03 and get 51! But, it would not make sense for the price ten years ago to be 51 then go to 1.53, so we make 51 a decimal, 0.51. We can check to see if this correct, by doing 0.51 times 3, because the price is tripling, and we get $1.53! Have an awesome day! :)

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at a party, everyone shook hands with everybody else. there were 66 handshakes. How many people shook hands?
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12

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Line p has an equation of y=-8x+6. Line q, which is perpendicular to line p, includes the point (2,–2). What is the equation of
Arturiano [62]

Answer:

y =  \frac{1}{8} x - 2  \frac{1}{4}

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is the y-intercept

Line p: y= -8x +6

slope= -8

The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.

m(-8)= -1

m= -1 ÷(-8)

m= ⅛

Substitute m= ⅛ into the equation:

y= ⅛x +c

To find the value of c, substitute a pair of coordinates that the line passes through into the equation.

When x= 2, y= -2,

-2= ⅛(2) +c

- 2 =  \frac{1}{4}  + c

c =  - 2 -  \frac{1}{4}

c =  - 2 \frac{1}{4}

Thus, the equation of line q is y =  \frac{1}{8} x - 2 \frac{1}{4}.

4 0
2 years ago
If we transform y=x^2 by 5 units to the left and 8 units ups, what is the vertex of the resulting parabola?
sertanlavr [38]

Answer: y = (x + 5)² + 8

<u>Step-by-step explanation:</u>

y = x²

left 5 units:       y = (x + 5)²

up 8 units:        y = (x + 5)² + 8

7 0
3 years ago
Read 2 more answers
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