You would probably need to divide. <span>Inches
-------- = 30/3 = 10.
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Integration by parts will help here. Letting 

 and 

, you end up with 

 and 

. Now


For the remaining integral, setting 

 gives 

, so

Putting everything together, you end up with
 
 
        
        
        
Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be  .
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
 , where,
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:  .
.
Amount of interest earned from higher-yielding account:  .
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be  .
.
Therefore, the man invested $60,000 at 6%.
 
        
             
        
        
        
Answer:
If a is 1.. we substitute one in every a in g(a)
4 * 1 + 16
4+ 16 = 20
g(a)= 20
f(20)
-16 + 20 = 4
and 4/4 = 1
so f (g (a)) = a
Step-by-step explanation:
 
        
             
        
        
        
Answer:
27
divide 42 by 33 and multiply by 100 =127