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3 years ago

Find the slope and the y-intercept of the line

Mathematics

1 answer:

Rom4ik [11]3 years ago

3 0

Answer:

the slope of the line is 4

m = 4

y-intercept is -8

y = 4(0) - 8 = 0 - 8 = -8

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7(3+5)= ___+___<br><br> 15-10=___ (3-2)<br> (20 points)

stich3 [128]

Answer:

7(3+5)= 7×3+7×5=21+35=56

15-10=5(3-2)=5×1=5

6 0

2 years ago

Read 2 more answers

Beth and Sarah are selling candy for a school fundraiser. Customers can buy small boxes of candy and large boxes of candy. Beth

Scrat [10]

Answer:

Cost of small box = $13

Cost of large box = $18

Step-by-step explanation:

Let the cost of small box of candy = $s

And the cost of large candy box = $b

Beth sold 9 small and 10 large boxes of candies for $297.

9s + 10b = 297 -----(1)

Sarah sold 8 small and 5 large boxes of candies for $194.

8s + 5b = 194 -------(2)

Multiply equation (2) by 2 then subtract equation (1) from (2).

2(8s + 5b) - (9s + 10b) = (2×194) - 297

16s + 10b - 9s - 10b = 388 - 297

7s = 91 ⇒ s = $13

From equation (2),

(8×13) + 5b = 194

104 + 5b = 194

5b = 90

b = $18

6 0

3 years ago

Evaluate (2/3) to the third power + 2 + 7/9

Jobisdone [24]

We have 8/27 + 25/9 = 24/81 + 225/81 = 249/81 = 3.07;

5 0

2 years ago

Read 2 more answers

You plan to buy $12,000 in computers at a local chain store. There are two stores located about the same distance from your offi

inysia [295]

the last one is the correct answer

how I did this is i did 8.5-7=1.5

4 0

2 years ago

For a special sale, a mens tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties and wants to achi

zlopas [31]

Answer:

The average cost of each tie is $56.350

Step-by-step explanation:

We are given that a men tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties

So, Cost of 450 ties = $450 \times 39.99=17995.5$

An order for 100 ties that cost $20.00 each

Cost of 100 ties = $100 \times 20 = 2000$

Total cost price = 17995.5+2000 = 19995.5

Let the selling price of 1 tie be x

Total ties = 450+100 = 550

So, SP of 550 ties =550x

Now we are given that markup is 55%

So, Profit % = 55%

So, $CP = \frac{SP \times 100}{100+P\%}$

Substitute the values

$19995.5 = \frac{550x \times 100}{100+55}$

$19995.5 = \frac{550x \times 100}{155}$

$19995.5 \times 155 = 55000x$

$\frac{19995.5 \times 155}{55000}=x$

$56.350=x$

Hence The average cost of each tie is $56.350

7 0

2 years ago