To start with, we know there’s a definite amount of parking spaces in all(2,250) and we also know each level(6 in all) had 15 rows of parking spaces.
Equation
A = Parking spots per row
A = 2,250 Divided by(6 levels times 15 rows)
A= 2,250 Divided by 90
A = 25
The correct answer is 25 parking spots per row
To check this answer we can do
25 spots per row, Times 15 rows per level, Times the total amount of levels (6)
= the total amount of parking spots
25*15*6= 2,250
True
This confirms this answer as correct. Hope this helps.
Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
The additional true statement that would need to be given in order to state the conclusion using the law of detachment is 49,700 is divisible by 100.
<h3 /><h3>What is law of detachment?</h3>
Law of detachment states that if a facts is true and its hypothesis is true, then its conclusion is true.
For instance,
Statement A: If there's an increase in Mr Charles salary.
Statement B: Mr Charles buys bicycle for his son.
This means Mr Charles buying bicycle for his son is true because of the increase in income.
Learn more about law of detachment:
brainly.com/question/13966470
#SPJ1
Answer:
x=0.59
Step-by-step explanation:
because if u divide 5.9 by 10 it will give u 0.59
and isolate x
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
