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My name is Ann [436]
3 years ago
14

What is the answer of 7-4x=2-9x

Mathematics
2 answers:
elena55 [62]3 years ago
8 0

Answer:

X= - 1

Step-by-step explanation:

7−4x=2−9x

7+−4x=2+−9x

−4x+7=−9x+2

Step 2: −4x+7+9x=−9x+2+9x

5x+7=2

Step 3: 5x+7−7=2−7

5x=−5

Step 4: 5x

5

= −5

5

x=−1

julia-pushkina [17]3 years ago
5 0
7-4x=2-9x the answer is x=1
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Which statement is true regarding triangle TU?
blsea [12.9K]

Answer:

angle v is the smallest

Step-by-step explanation:

3 0
3 years ago
Solve the system: <br> 2/x - 3/y =-5; 4/x + 6\y =14
sertanlavr [38]

The solution is x = 2 \text{ and } y = \frac{1}{2}

<em><u>Solution:</u></em>

Let us assume,

a = \frac{1}{x}\\\\b = \frac{1}{y}

<em><u>Given system of equations are:</u></em>

\frac{2}{x} - \frac{3}{y} = -5

\frac{4}{x} + \frac{6}{y} = 14

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

4a - 6b = -10 ------------- eqn 3

<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

a = \frac{4}{8}\\\\a = \frac{1}{2}

Substitute a = 1/2 in eqn 1

2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2

Substitute b = 2 in assumed value

b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}

Thus the solution is x = 2 \text{ and } y = \frac{1}{2}

3 0
2 years ago
Vidhur is thinking of a three digit number.
antoniya [11.8K]
I think there are 200 numbers as if we do 1000-800 (10-8 as there are only 2 numbers that can be divided by 5 exactly up to 10) that leaves 200 numbers
3 0
2 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
80,607.202 rounded to the nearest tens place is
postnew [5]
It’s 80,610 if you really mean the tens place.
If you mean the one tenths place then it’s 80,607.2
5 0
3 years ago
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