9. In two years it would be (2,20) find the point on the grid and mark the spot.
In three years it would be (3,40) also mark that spot on the grid.
In four years it would be (4,80) mark this point on the grid
All I'm doing is finding the number of the year and going up till it meets the red line or population amount.
Hope this helped you a little.
If x = 1, then 3*1 = 3 which when modded with 5, we get 3 as a remainder. In other words, 3/5 = 0 remainder 3. We don't use the quotient at all when it comes to modular arithmetic. All we care about is the remainder.
If x = 2, then 3*2 = 6 which leads to remainder 1 when we divide by 5. Therefore, 3x = 1 (mod 5) when x = 2.
If x = 3, then 3*3 = 9 = 4 (mod 5) because 9/5 = 1 remainder 4.
So 3x = 4 (mod 5) when x = 3.
<h3>The final answer is C) 3</h3>
We don't need to check D since x = 3 is a solution and it's smaller than x = 4.
If you wanted to check x = 4, then 3*4 = 12 = 2 (mod 5) because 12/5 yields a remainder of 2.
Answer:
Here we have two inequalities.
P is price of the gallon,we have that:
$2.40 ≤ P ≤ $2.65
C is the amount of gallons that Ricardo buys each week.
8,5 ≤ C ≤ 11
Now, with this you can find the maximum and minimum amount that he can spend on a week.
The minimum is when he buys only 8.5 gallons and the price per gallon is $2.40
Cost = 8.5*$2.40 = $20.4
The maximum cost is when he buys 11 gallons, and the price of the gallon is $2.65
Cost = 11*$2.65 = $29.15
So the amount that he spends per week in gas, S, is:
$20.4 ≤ S ≤ $29.15
Answer: year 2194
Explanation:
1) Model the jump of the women:
i) initial jump = 70.0 in
ii) increase rate = 0.48% per year
iii) equation: h = 70.0(1 +0.0048)ⁿ
2) Model the jump of the men:
i) initial jump 86.5 inches.
ii) increase rate, 0.4%.
iii) equation: h = 86.5 (1 + 0.004)ⁿ
3) Equal the two equations (h = h) to find when the jumps will be equal:
i) 70.0(1 +0.0048)ⁿ = 86.5 (1 + 0.004)ⁿ
ii) 70.0(1.0048)ⁿ = 86.5 (1.004)ⁿ
ii) [1.0048ⁿ / 1.004ⁿ] = 86.5/70.0
iii) [1.0048/ 1.0040]ⁿ = 86.5/70.0
iv) n log (1.0048 / 1.0040) = log ( 86.5/70)
v) n = log (86.5/70) / log (1.0048/1.0040) ≈ 266
3) year = 1928 + 266 = 2194
That is in the year 2194
The surface area (SA) of a cube can be written as:
SA = 6s²
From here we can write, the length of the side s as:
For cube with surface area of 1200 square inches, the side length will be:
inches
For cube with surface area 768 square inches, the side length will be:
inches
The difference in side lengths of two cubes will be:
Rounding to nearest tenth of an integer, the difference between the side lengths of two cubes will be 2.8 inches.
