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alex41 [277]
3 years ago
7

A certain television is advertised as a 50-inch TV (the diagonal length). If the width of

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Hello there i hope you are having a great day :) Your question: A certain television is advertised as a 50-inch TV (the diagonal length). If the width of  the TV is 14 inches, how many inches tall is the TV?

So you would need to used the Pythagorean theorem that would be

c^2 = a^2 + b^2

So this would equal letter C as The hypotenuse of the right angle and also letter A and B are the stands on the triangle so C would equal 50 inches and A and B would equal 14 inches.

Then the Hard bit so you would be,

1) a^2 = c^2 - b^2

2) a = √c^2 - b^2

3) a =  50^2 - 14^2

4) a = √ 2,500 - 196

5) a = √2,304

6) A = 26

So the answer would be 26 Hopefully ❤

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Find the area of this irregular figure. Please explain in steps how you did it so I know how to do it for the next question plea
Helen [10]
<h3>Answer:   426 square feet</h3>

Work Shown:

A = area of the rectangle

A = length*width

A = 26*15

A = 390 square feet

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7 0
1 year ago
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8 0
2 years ago
Read 2 more answers
Can someone help please
myrzilka [38]
<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

3 0
2 years ago
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