Slope of 5 and goes through the origin

Two ships leave from the same port. One travels west 84 miles and the other travels 62 miles north. Determine the distance betwe

Lerok [7]

The distance the ships traveled are like the legs of a triangle and the question wants to know the hypotenuse. To find the hypotenuse, use the pythagorean theorem. this is a^2 + b^2 = c^2, with a and b being the legs and c being the <span>hypotenuse.
</span>Plug in known values:
84^2 + 62^2 = c^2
Solve:
84^2 = 7056
62^2 = 3844
7056 + 3844 = c^2
7056 + 3844 = 10900
10900 = c^2
Now you just need to isolate c by finding the square root of both sides.
√10900 = 104.403
√c^2 = c

So c = 104.403, or just 104.40 when rounded to the nearest tenth.
And if c is 104.40, then that means the hypotenuse is 104.40.
And all of that basically means that the distance between the ships is 104.40 miles.

5 0

3 years ago

What’s the area of this rounded to the nearest one’s place?

Shkiper50 [21]

Answer:

I think I might be terribly wrong but 160,728 ft

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A) An empty bulldozer weighed 5 8 ⁄10 tons. If it scooped up 7 1 ⁄10 tons of dirt, what would be the combined weight of the bull

irakobra [83]

Answer: 12 9/10 and 10 7/8

Step-by-step explanation:

5 8/10 plus 7 1/10 equals 12 9/10

8 5/8 plus 2 2/8 equals 10 7/8

6 0

3 years ago

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$