Answer:
no, this is not a function
Step-by-step explanation:
i hope this helps :)
Answer:
answer is 9cm
opposite side of trapezium are equal
hopes this helps u
<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>

<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>

To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,

Solve the inequality
Subtract 1000 from both sides


Time cannot be negative
Therefore,
t < 6.61
And the inequality used is: 
Answer:
It's 38.1
Step-by-step explanation:
I'm not the best at explaining these type of things but I hope this helps you out
The statement logically equivalent to the statement below will be
,,If today is Weekend,then it is not the Monday ."