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3 years ago

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Mathematics

1 answer:

madam [21]3 years ago

7 0

Answer:

77% and as a fraction it would be 77/100

Step-by-step explanation:

0.77 is a decimal that is in the hundredths place so you already know that it'll be 77% right away then for the fraction you would just put it over 100 but since 77 is an uneven number you cannot simplify it otherwise you would.

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If the hikers want to share the fruit evenly how many pieces should each person receive ?

Ivan

Is there a photo to attach to this? Number of hikers, number of fruit would be appreciated.

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3 years ago

PLEASE HELP!<br><br> Reduce to simplest form.<br> 5/8 - (- 7/2)

Daniel [21]

Answer:

$\huge\boxed{\sf 4\frac{1}{8} }$

Step-by-step explanation:

$\sf =\frac{5}{8} - (-\frac{7}{2} )\\\\Rule : ( - *- = +)\\\\\=\frac{5}{8} +\frac{7}{2} \\\\LCM = 8\\\\\=\frac{5+28}{8} \\\\\=\frac{33}{8} \\\\=4\frac{1}{8}$

$\sf =\frac{5}{8}+ \frac{7}{2} \\\\=\frac{5+28}{8}$

$\sf =\frac{33}{8} \\\\=4\frac{1}{8}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

7 0

3 years ago

Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively?

MariettaO [177]

There is no given data table but based on the question, the reaction is
xy <=> x + y
If we let M as the initial concentration of xy and c as the in the concentration after the dissociation, then we can use the ICE method
xy <=> x + y
I M
C -c c c
-----------------------------
E M-c c c

Solve for c using
Kc = c(c) / (M - c)
And the concentration of the xy, x, and y can then be determined

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3 years ago

Unit activity: exponential and logarithmic functions

nirvana33 [79]

We will conclude that:

The domain of the exponential function is equal to the range of the logarithmic function.
The domain of the logarithmic function is equal to the range of the exponential function.

<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

y > 0.

For the logarithmic function we have:

g(x) = A*ln(x).

As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

$\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty$

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>

The domain of the exponential function is equal to the range of the logarithmic function.
The domain of the logarithmic function is equal to the range of the exponential function.

If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

3 0

2 years ago

On a loan of $4,500 for 2 1/2 years at 4% per year, how much do you wind up paying to pay off the loan?

Strike441 [17]

4/100= x/4,500
18,000/100= $180x2.5 = $450

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3 years ago