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Pachacha [2.7K]
2 years ago
11

Please help me plzzzz

Mathematics
1 answer:
joja [24]2 years ago
8 0

Answer:

pretty sure its 12-g

Step-by-step explanation

because adding 0 is just adding nothing so you can omit the 0 and not change anything.

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(Giving Brainliest♡)
frutty [35]

Answer:

15

Step-by-step explanation:

Hi there! :)

If you created 5 circles cut into thirds, you would create 15 1/3 pieces.

You can also use the KCF method to solve this!

7 0
3 years ago
If a circle has a diameter of 91 units how many units is the radius
deff fn [24]

Answer:

r =45.5 units

Step-by-step explanation:

The diameter is twice the radius, or the radius is 1/2 the diameter

r = d/2

r = 91/2

r =45.5 units

7 0
3 years ago
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You have prizes to reveal! Go to your game board. X
Delicious77 [7]
B. cdb ....angle cdb is adjacent to angle adb because they have a common side (line db)
8 0
3 years ago
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Find the value of cos G rounded to the nearest hundredth.
Amiraneli [1.4K]

Answer:

\sf \cos(G)=\dfrac{1}{2}

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = G
  • A = GF = 2
  • H = EG = 4

\implies \sf \cos(G)=\dfrac{2}{4}=\dfrac{1}{2}

8 0
1 year ago
Read 2 more answers
Three balanced coins are tossed independently. One of the variables of interest is Y1, the number of heads. Let Y2 denote the am
sesenic [268]

Answer:

a) the joint probability distribution function is

P(y1,y2)=

      C(3-y1,y2-1)/8, for 1≤y2≤4-y1 and 1≤y1≤3 ,

      1/8 for (y1,y2)=(-1 ,0)

       0 otherwise

b) the probability is 50% (F(2,1)= 1/2)

Step-by-step explanation:

for the variable Y1, we start with the negative binomial distribution, with true or false values:

p(r,x)=C(x+r-1,r-1)*p^r*(1-p)^x , where x= number of false experiments until a number r of true values is achieved, and C(a,b)=number of combinations of b in a values. if we set r=1 (fist head) and y1=x+1 (except of y1=-1)

p(y1)= C(y1,0)*p^0*(1-p)^(y1-1) = p*(1-p)^(y1-1)

for the variable Y2, we begin with the binomial distribution:

p(n,x)= C(n,x)*p^x*(1-p)^(n-x) , n= number of times the coin is tossed, x= number of heads obtained , p = probability of obtaining heads when the coin is tossed once.

if we set n=3-y1 (remaining coins that can be tail or head), and x=y2-1 (since we already know the first head appeared), we calculate the probability of p(y2) in case of y1 ( or p(y2|y1) )

p(y2|y1)= C(3-y1, y2-1)*p^(y2-1)*(1-p)^(4-y1-y2)

Now using the theorem of Bayes:

P(y2,y1)=p(y2∩y1)=p(y2|y1)*p(y1) = C(3-y1,y2-1)*p^y2*(1-p)^(3-y2)

since the coins are balanced p= 0,5

P(y2,y1)= C(3-y1,y2-1)*0,5^y2*(1-0,5)^(3-y2)= C(3-y1,y2-1)*0,5^3=C(3-y1,y2-1)/8

therefore

P(y2,y1)=

      C(3-y1,y2-1)/8, for 1≤y2≤4-y1 and 1≤y1≤3 ,

      1/8 for (y1,y2)=(-1 ,0)

       0 otherwise

b) F(2,1)= P(y=1,y2<2)+P(y=(-1),y2=0)= [C(2,0)/8+C(2,1)/8] + 1/8 = (1/8+2/8)+1/8=4/8=1/2

6 0
2 years ago
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