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dusya [7]
3 years ago
8

Joey practices the guitar every 11th day and the trombone every 3rd day. Joey practiced both the guitar and the trombone today.

How many days did Joey practices the guitar and the trombone again in the same day?
Mathematics
1 answer:
densk [106]3 years ago
6 0

11 = 11*1

3=3*1

least common multiple = 3*11*1 = 33

33 days from today he will practice the guitar and the trombone

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Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0
gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0

Divide this by t to get in linear form

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This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/te^(\int 1/tdt) = t

So solution would be

yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C

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3 years ago
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Mrrafil [7]

Answer:

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2 years ago
Physics students were modeling the height of a ball once it was dropped from the top of a 10 foot ladder. The
julsineya [31]

Answer:

<em>Interval notation: [0, 2.236]</em>

<em>Set Builder notation: </em>\{t\ |\ 0\le t\le 2.236\}

Step-by-step explanation:

Given that:

Equation of height of the ball dropped from a height of 10 foot, as:

h(t) = 10 - 2t^2

Where t is the time since the ball was dropped.

To find:

The domain of the function in Interval and set builder notation.

Solution:

<em>Domain of a function </em>is defined as the set of valid input values that can be given to the function for which the function is defined.

Here, input is time.

We can not have negative values for time.

Therefore, starting value for time will be <em>0 seconds</em>.

And the value of height can not be lesser than that of 0 ft.

0= 10 - 2t^2\\\Rightarrow 2t^2=10\\\Rightarrow t^2=5\\\Rightarrow t =2.236\ seconds

Maximum value for time can be 2.236 seconds.

Therefore the domain is:

<em>Interval notation: [0, 2.236]</em>

<em>Set Builder notation: </em>\{t\ |\ 0\le t\le 2.236\}

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3 years ago
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kogti [31]

Answer:

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Step-by-step explanation:

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Add numerators:

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Upon multiply both sides of our equation by \frac{6}{7}, we will get:

\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}

x=\frac{5*6}{7}

x=\frac{30}{7}

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