Find all real fourth roots of 16. 2 and -2 4 and -4
1 answer:
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Hi!
I'm not sure how to slove this, but I do know how to solve it ;D
<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>x + y = 3 * z
<h3>Now subtract x from both sides.</h3>x - x + y = 3 * z - x
<u>y = 3 * z - x</u>
<h2>The answer is y = 3 * z - x</h2>Hope this helps! :)
-Peredhel
Answer:
The positive numbers are 51 and 53
Step-by-step explanation:
Let first odd integer be x and another odd integer is (x+2).
According to the given condition,
The product of two positive consecutive odd integers is 2703 i.e.
x(x+2) = 2703
It is a quadratic equation. It can be solved as follows :
x = 51 and x = -53
Neglecting negative sign,
The first number = 51
Another number =(51+2) = 53
Hence, the positive numbers are 51 and 53.