The equation of a circle with center (h,k) and radius r is
(x-h)²+(y-k)²=r²
so
given center is (3,-4)
(x-3)²+(y-(-4))²=r²
(x-3)²+(y+4)²=r²
find r² by subsitutiong the point taht it passes through which is (6,5)
so
(6-3)²+(5+4)²=r²
3²+9²=r²
9+81=r²
90=r²
so
(x-3)²+(y+4)²=90 is da equation
4th equation
Step-by-step explanation:
a x^2/4
b -x^2/4+3
c 4x^2
d -x^2
How is anyone gonna know that lol
Answer:
135 degrees
Step-by-step explanation:
It is as isosceles trapezoid, so the the base angles are congruent. The sum of the inner angles is 360 degrees
2(4x-7) + 2(11x -8) = 360
8x - 14 + 22x -16 = 360
30x = 390
x = 13
angle F = angle G
angle G = 11 * 13 - 8 = 135 degrees
