Answer:
answer a
Step-by-step explanation:
Y= a(x-3)^2+6
2= a(0-3)^2+6
2=a(-3)^2+6
2=a(9)+6
2-6=9a
-4=9a
-4/9=a
Therefore the equation in vertex form is
y = -4/9 (x-3)^2+6
Step-by-step explanation:
TO FIND THE DOMAIN OF THIS FUCTION AVOID SITUATIONS LIKE Y=2/0 FOR THIS IS UNDEFINED.
TAKING THE DENOMINATOR AND EQUATING IT TO ZERO
=> X – 6 =0
=> X=6
SO AVOID HAVING X = 6 IN THE DENOMINATOR FOR WHICH THE FUNCTION WILL BECOME UNDEFINED
THEREFORE, X ≠6
DOMAIN ={ X£R, x ≠6}
I.e all real numbers except 6
your answer is a ok i hope this helpful
Answer: 3
Step-by-step explanation: QPEX VERIFIED JUST DID IT
