I am not sure, but this is what I got:
<span>Pipe ALONE = 18 hours

Pipe ALONE in 1 hour = 1/18 of the pool

Hose ALONE in 1 hour = 1/25 of the pool

TOGETHER in 1 HOUR = 1/18 +1/25 = 43/450

TOGETHER they will fill the pool in 450/43 hours

So 5/6 of the pool will take 5/6 X 450/43 = 2250/ 258 = 8.7209302 hours OR

8 hours AND 43.26 minutes ANSWER
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Hope this helps!

6 0

3 years ago

The output is the cube of the input.

chubhunter [2.5K]

Yes it is right because you are measuring by either the base to height or length times width

4 0

3 years ago

Please help (20 points)

Evgesh-ka [11]

$35.\\V=\dfrac{\pi r^2h}{3}\ \ \ \ |\cdot3\\\\3V=\pi r^2h\ \ \ \ |:\pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}$

$36.\\V=150\ m^3\\r=5\ m\\h=?\\\\\text{substitute}\\\\h=\dfrac{3\cdot150}{\pi\cdot5^2}=\dfrac{450}{25\pi}=\dfrac{18}{\pi}\approx\dfrac{18}{3}=6\ m\\\\Answer:\ The\ height\ is\ greater\ than\ a\ radius.$

8 0

4 years ago