All categories

3 years ago

Math help can someone help me with the first three?

Mathematics

2 answers:

Licemer1 [7]3 years ago

4 0

1. minus 3
2. 38
3. yes

ycow [4]3 years ago

4 0

Tuesday is 3 less, Wednesday is 4 less, and Thursday is 5 less. For some reason, I can't find the words to describe that pattern but I know that the number of students will probably be 35 on Friday which is a decrease of 6 from Thursday. The pattern can't go on forever because if it keeps decreasing it'll eventually reach negatives and there can't be an attendance of a negative amount of students. Hope that helped, sorry I wasn't very well at explaining the first question but I hope I clarified it a bit. :)

You might be interested in

Help me please solves this my math teacher will yell at me if I don’t get this done!!!

VARVARA [1.3K]

The answer is 75

First you subtract 180 and 165 to find that smallest angle inside the triangle(15). Then you add 15 and 90,the two angles you know, and do 180 - 105= 75.

The trick is that all angles inside a triangle equal 180 degrees. Hope this helps!

5 0

4 years ago

a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s

Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, $s^{2}$ = sample variance = $97^{2}$ = 9409

n = sample of boxes = 15

$\sigma^{2}$ = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, $\sigma^{2}$ is ;

P(5.629 < $\chi^{2}__1_4$ < 26.12) = 0.95 {As the critical value of chi-square at 14

degree of freedom are 5.629 & 26.12}

P(5.629 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 26.12) = 0.95

P( $\frac{5.629 }{(n-1)s^{2} }$ < $\frac{1}{\sigma^{2} }$ < $\frac{26.12 }{(n-1)s^{2} }$ ) = 0.95

P( $\frac{(n-1)s^{2} }{26.12 }$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{5.629 }$ ) = 0.95

<u><em>95% confidence interval for</em></u> $\sigma^{2}$ = [ $\frac{(n-1)s^{2} }{26.12 }$ , $\frac{(n-1)s^{2} }{5.629 }$ ]

= [ $\frac{14 \times 9409 }{26.12 }$ , $\frac{14 \times 9409 }{5.629 }$ ]

= [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0

3 years ago

3x + y = 8<br><br> -x + y = -4<br> Solve the system. Write your answer as an ordered pair (x, y)

timurjin [86]

I hope this helps you

x=y+4

3 (y+4)+y=8

3y+12+y=8

4y= -4

y= -1

x= -1+4

x=3

(3, -1)

8 0

4 years ago

What is 5 6/7 + 8 1/14=

Fittoniya [83]

$5\frac{6}{7}+8\frac{1}{14} =13+\frac{13}{14}=13\frac{13}{14}$

<h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

7 0

3 years ago

Two integers whose product is 90 and whose sum is 21

Likurg_2 [28]

Answer:

6 and 15

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers