MARK BRAINLIEST!!
So your solution is.
=−5
Answer: B) y=6/11.
To find the horizontal asymptote(s) you must find the limit as x approaches infinity and the limit as x approaches -infinity.
Using L’Hôpital’s rule:
lim x-> infinity (f(x))=6/11.
lim x-> -infinity (f(x))=6/11.
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.
Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.
Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7
Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18
Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.
Answer: 37,39,41,43
Answer:
-11
Step-by-step explanation:
let (2,1)be x1 and y1 respectively
(3,-10) be x2 and y2 respectively
From,slope= (y2-y1)/(x2-x1)
=(-10-1)/(3-2)
= -11/1
= -11
