Ask question

Ask question

All categories

Vedmedyk [2.9K]

3 years ago

12

Pemdas? thank you!(-12 ÷ 3) × 2 + 23

1 answer:

lana66690 [7]3 years ago

3 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$( - 12 \div 3) \times 2 + 23 =$

$( - 4) \times 2 + 23$

$- 8 + 23 =$

$23 - 3 - 5 =$

$20 - 5 = 15$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

You might be interested in

Melinda is planning for retirement so she makes monthly deposits of $420 in an account earning 5% compounded monthly for 30 year

trapecia [35]

A) 5/100 x 420 = 21
21 x 12 x 3= 756
420 x 12 x 3 = 15,120
15,120+756= 15,876

b) 4/100 x 420= $16.8

5 0

3 years ago

Slide the stick figures to the zeros of the function. Then move their arms to match the behavior of the function.

lesantik [10]

Answer:

no clue but good luck bro

Step-by-step explanation:

7 0

3 years ago

Can someone please help, will give the brainiest.

Studentka2010 [4]

Answer:

Step-by-step explanation:

As it is supposed to be linear, we just subtract two adjacent months to find the difference.

$13,849.60 - $13,610.81 = $238.79 which will be her monthly payment (Q 14)

December's balance is $13,610.81 - $238.79 = $13,372.02 (Q13)

At the end of September, her first payment, her balance was

$13,849.60 + $238.79 = $14,088.39 and her original purchase price was

$14,088.39 + $238.79 = $14,327.18

so an equation for the current balance B at any month m is

B = (-$238.79)m + $14,327.18

We verify this by testing for February

B = (-$238.79)6 + $14,327.18 = $12,894.44 which checks out

It will take 14327.18 / 238.79 = 60 months to pay it off or 5 years (Q 15)

5 0

3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

4 years ago

What is 8−2⋅3+7<br> Needs Help badly

Svetach [21]

8-2.3+7
8 - 9.3
-1.3 answer

4 0

2 years ago

Read 2 more answers