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Anna [14]
3 years ago
13

How do I write this expression:The quantity seven plus Z, squared

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

  (7+Z)²

Step-by-step explanation:

A less ambiguous way to describe the quantity might be "the square of the quantity seven plus Z".

As it is, we rely on the presence of the comma to tell us that the quantity to be squared is (7+Z). If the comma were not present, we would assume you want to add 7 to the square of Z: 7+Z².

  the quantity 7 plus Z: (7+Z)

  that quantity squared: (7+Z)²

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How do I solve 4x-2(x-5) = -7+5x+2​
natta225 [31]

Answer:

x=5

Step-by-step explanation:

1) Group like terms which will then make the equation 4x-2(x-5)=5x-5

2) Expand the equation (multiply) which will make it 4x-2x+10=5x-5

3) Add similar elements; 2x+10=5x-5

4) Subtract 10 from both sides; 2x=5x-15

5) Subtract 5x from both sides; -3x=-15

6) Divide by 3; x=5

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How many solution does the equation 5x+8=2x-1 wil have.
elixir [45]

Answer:

1 solution. Solution is -3.

Step-by-step explanation:

First subtract 8 from both sides. This gives you 5x=2x-9.

Then subtract 2x from both sides. This gives you 3x= -9

Next divide both sides by 3. This would give you that x = -3.

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What’s the sum of two over five and two/4
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3 years ago
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Show that a^12 can be written as a perfect square and a perfect cube
Elden [556K]

Answer:

Step-by-step explanation:

Doing this the long way, write a^12 as a product of "a"s

a^12 = a * a * a * a * a * a * a * a * a * a * a * a

Now group them into groups of 4

a^12 = a * a * a * a * a * a * a * a * a * a * a * a

There are 3 groups of 4 so you can write it as [(a^4)]^3 which is a cube

Now do the same thing with groups of 6s

a^12 = a * a * a * a * a * a * a * a * a * a * a * a

a^12 = (a^6)^2

So the two answers are

Perfect cube:  [(a^4)]^3

Perfect square: (a^6)^2

3 0
3 years ago
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