What is the intersection of lines for the equations y=x+1 and y=-x+5?

Let A = {Dirk, Johan, Frans, Sarie}, B = {Frans, Sarie, Tina, Klaas, Henrika}, C = {Hans, Frans}. Find the number indicated. n(A

olchik [2.2K]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \bold{9}}}}}$

Step-by-step explanation:

Given,

A = { Dirk , Johan , Frans , Sarie }

B = { Frans , Sarie , Tina , Klass , Henrika }

To find : n ( A ) + n ( A )

Now, count the number of member of a set A

n ( A ) = 4

Also, Count the number of members of a set B

n ( B ) = 5

Finding n( A ) + n ( B )

= 4 + 5

= 9

Hope I helped!

Best regards! :D

6 0

3 years ago

Solve this proportion. 9/n=7/5

Irina18 [472]

Answer:

n = 6 3/7 or 45/7

Step-by-step explanation:

cross-multiply

7n = 45

n = 45/7 or 6 3/7

8 0

3 years ago

Read 2 more answers

Fine the lower and upper quartiles and interquetile range.

Gnom [1K]

Answer:

Lower Quartile = 25.5

Upper Quartile = 61.5

IQR = 36

Step-by-step explanation:

Given data is:

5, 12, 17, 23, 28, 31, 37, 41, 42, 49, 54, 58, 65, 68, 73, 71

The lower quartile is the first quartile and upper quartile is the third quartile.

A median divides the data set in two equal halves.

Lower quartile also known as first quartile is the middle value in the first half.

The first half is:

5, 12, 17, 23, 28, 31, 37, 41

As the number of values is even, the quartile will be the average of two middle values

$Q_1 = \frac{23+28}{2} =\frac{51}{2}= 25.5$

Upper quartile is the average of middle two values in the second half when the number of values is even.

42, 49, 54, 58, 65, 68, 73, 71

$Q_3 = \frac{58+65}{2} = \frac{123}{2} = 61.5$

Interquartile range is the difference of third quartile and first quartile

$IQR = Q_3 - Q_1 = 61.5-25.5=36$

Hence,

Lower Quartile = 25.5

Upper Quartile = 61.5

IQR = 36

7 0

3 years ago

There is a line through the origin that divides the region bounded by the parabola y=2x-4x^2 and the x-axis into two regions wit

shtirl [24]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

y = 7x - 4x²

7x - 4x² = 0 

x(7 - 4x) = 0 

x = 0, 7/4 

Find the area of the bounded region... 

A = ∫ 7x - 4x² dx |(0 to 7/4) 

A = 7/2 x² - 4/3 x³ |(0 to 7/4) 

A = 7/2(7/4)² - 4/3(7/4)³ - 0 = 3.573 

Half of this area is 1.786, now set up an integral that is equal to this area but bounded by the parabola and the line going through the origin... 

y = mx + c 

c = 0 since it goes through the origin 

The point where the line intersects the parabola we shall call (a, b) 

y = mx ===> b = m(a) 

Slope = m = b/a 

Now we need to integrate from 0 to a to find the area bounded by the parabola and the line... 

1.786 = ∫ 7x - 4x² - (b/a)x dx |(0 to a) 

1.786 = (7/2)x² - (4/3)x³ - (b/2a)x² |(0 to a) 

1.786 = (7/2)a² - (4/3)a³ - (b/2a)a² - 0 

1.786 = (7/2)a² - (4/3)a³ - b(a/2) 

Remember that (a, b) is also a point on the parabola so y = 7x - 4x² ==> b = 7a - 4a² 
Substitute... 

1.786 = (7/2)a² - (4/3)a³ - (7a - 4a²)(a/2) 

1.786 = (7/2)a² - (4/3)a³ - (7/2)a² + 2a³ 

(2/3)a³ = 1.786 

a = ∛[(3/2)(1.786)] 

a = 1.39 

b = 7(1.39) - 4(1.39)² = 2.00 

Slope = m = b/a = 2.00 / 1.39 = 1.44

7 0

3 years ago

A club held a car wash as fund-raiser.they charged $20 for trucks and $15 for cars.the club washed a total of 35 vehicles and ea

Ivenika [448]

Answer:$585

Step-by-step explanation:

5 0

2 years ago