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3 years ago

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Human civilization, at least since the time of ancient Egypt, is on the order of 5000 years old. The age of the Earth is on the

order of 5 billion years. Suppose we use the length of a football field, or about 100 meters, as a timeline to represent the age of the Earth. If we put the birth of the Earth at the start of the timeline, how far from the start of that line would human civilization be?

1 answer:

olchik [2.2K]3 years ago

5 0

Write and solve an equation of ratios:

5 *10^9 years 100 m
------------------- = --------------
5 * 10^3 yrs x

Reducing the first fraction,

100 m
10^6 = ----------
x
100 m
Solving for x, x = ------------- = 10^(-4) m, or [10^(-1)] * [10^(-3))]
10^6
this comes out to one tenth of 1 millimeter.

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(15P) PLEASE HELP ME ASAP NEED HELP!

olya-2409 [2.1K]

Answer:

x=7

y=2

Step-by-step explanation:

10 + 2x = -2y ➡y = -5-x

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Hey there, Lets solve this problem together.

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3 years ago

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An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholde

n200080 [17]

Answer:

(a)

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

(b)

$P(3 \le x \le 6) = 0.30$

$P(4 \le x)=0.60$

Step-by-step explanation:

Given

$F(x) = \left[\begin{array}{ccc}0& x$

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

The calculation is as follows:

$0.30 - 0 = 0.30$

$0.40 - 0.30 = 0.10$

$0.45 - 0.40 = 0.05$

$0.60 - 0.45 = 0.15$

$1 - 0.60 = 0.40$

The x values are gotten by considering where the equality sign is in each range.

$1 \le x < 3$ means $x = 1$

$3 \le x < 4$ means $x = 3$

$4 \le x < 6$ means $x=4$

$6 \le x < 12$ means $x = 6$

$12 \le x$ means $x = 12$

Solving (b):

$(i)\ P(3 \le x \le 6)$

This is calculated as:

$P(3 \le x \le 6) = F(6) - F(3-)$

From the given function

$F(6)= 0.60$

$F(3-) = F(1) = 0.30$

So:

$P(3 \le x \le 6) = 0.60 - 0.30$

$P(3 \le x \le 6) = 0.30$

$(ii)\ P(4 \le x)$

This is calculated as:

$P(4 \le x)=1 - F(4-)$

$P(4 \le x)=1 - F(3)$

$P(4 \le x)=1 - 0.40$

$P(4 \le x)=0.60$

8 0

3 years ago