All categories

3 years ago

Saw a board 5 ft 1 in. Long into six equal pieces. If the loss per cut is 1/5 in., how long will each piece be?

Mathematics

1 answer:

Pie3 years ago

5 0

Answer:

The length of each piece is 0.833 ft.

Step-by-step explanation:

Length of board, L = 5 ft 1 inch

loss per cut = 1/5 inch

The board should be cut by 5 times to get the 6 pieces.

The loss in 5 cuts = 5 x 1/5 = 1 inch

So, the length of each piece is

$L' =\frac{5 ft 1 in - 1in }{6}\\\\L' =\frac{5}{6}\\\\L' = 0.833 ft$

You might be interested in

Write the equation of the line that has a slope of 3 and passes through (5, 11)

Marina CMI [18]

Answer:

3x-4

Step-by-step explanation:

y=ax+b general type of the line

a is the slope

y=3x+b

put 5 instead of the x and put 11 instead of the y

11=15+b

b=(-4)

Equation is 3x-4

4 0

3 years ago

Q bisects PR, PQ=3y, and PR=42. Find y and QR.

Vedmedyk [2.9K]

|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

|PQ| = 3y; |PR| = 42; |QR|=?

subtitute

42 = 2(3y)
6y = 42 |divide both sides by 6
y = 7

|QR| = 3(7) = 21

3 0

3 years ago

What is the answer for 35=-7z

Oduvanchick [21]

If you're looking for the value of z, then the answer should be -5.

8 0

3 years ago

Read 2 more answers

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago

a school debate team has 4 girls and 6 boys. A total of 4 of the team members will be chosen to participate in the district deba

Gemiola [76]

4g and 6b and that's a total of 10 in all so you know it will be 1/2 if its going to be two out of two

5 0

3 years ago