Answer:
![P(X\geq 3.4)=0.0228](https://tex.z-dn.net/?f=P%28X%5Cgeq%203.4%29%3D0.0228)
Step-by-step explanation:
Given the mean is 3.2, standard deviation is 0.8 and the sample size is 64.
-We calculate the probability of a mean of 3.4 as follows:
#First determine the z-value:
![z=\frac{\bar X -\mu}{\sigma/\sqrt{n}}\\\\=\frac{3.4-3.2}{0.8/\sqrt{64}}\\\\=2.000](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%5Cbar%20X%20-%5Cmu%7D%7B%5Csigma%2F%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B3.4-3.2%7D%7B0.8%2F%5Csqrt%7B64%7D%7D%5C%5C%5C%5C%3D2.000)
#We then determine the corresponding probability on the z tables:
![Z(X\geq 3.4)=1-P(X](https://tex.z-dn.net/?f=Z%28X%5Cgeq%203.4%29%3D1-P%28X%3C3.4%29%5C%5C%5C%5C%3D1-0.97725%5C%5C%5C%5C%3D0.0228)
Hence, the probability of obtaining a sample mean this large or larger is 0.0228
Answer:
F=50
Step-by-step explanation:
F=5*10=50
A is the correct answer!!!
Answer:
50
Step-by-step explanation:
42+123=165
165+50=215
215+145=360