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Ivanshal [37]
3 years ago
7

10. 25 xº 40 Solve for x. Round to the nearest tenth

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

51.32

Step-by-step explanation:

∠B = arcsin(b·sin(A)a)

= 0.67513 rad = 38.682° = 38°40'56"

∠C = 180° - A - B = 0.89566 rad = 51.318° = 51°19'4"

c = a·sin(C)sin(A) = 31.22499

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
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The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

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So,f(a)=f(-4)=8/(-4)=-2.

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The series of f(x) is as under:

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Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

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1 year ago
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