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Dafna11 [192]
3 years ago
7

Which object hawhich object has the most gravitational potential energy?

Physics
1 answer:
Sav [38]3 years ago
3 0
Hi, we can do a comparisson. Recall that potential energy is defined as m*g*h where m is the mass in kg, g is gravitational acceleration (9.8m/s^2) and h is the height therefore:
A:B:C:D=30×g×1.5:20×g×2:30×g×2:20×g×1.5 since all of them have the term of g, we can "kill" the term hence we have that:
A:B:C:D=45:40:60:30  hence we know the option c has the most potential energy
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What would the velocity of an object be if it was on a 1.75m
JulijaS [17]

Answer:

T = 4 sec / 2 = 2 sec      period of revolution

S = 2 pi R = 2 * pi * 1.75 m = 11 m

V = S / T = 11 m / 2 sec = 5.5 m/s       speed of object

4 0
3 years ago
Your friend is bragging about his motorcycle. He claims that it can go from a stopped position to 50 miles per hour in three sec
nalin [4]
If the motorcycle can go from 0 to 50mph in 3 seconds the person is describing the motorcycle's acceleration. 
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3 years ago
Read 2 more answers
1pt A cannon fires a 5-kg ball horizontally from a
Klio2033 [76]

Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
A race car has a centripetal acceleration of 15.625 m/s2 as it goes around a curve. If the curve is a circle with radius 40 m, w
myrzilka [38]
The centripetal acceleration is given by
a_c =  \frac{v^2}{r}
where v is the tangential speed and r the radius of the circular orbit.

For the car in this problem, a_c = 15.625 m/s^2 and r=40 m, so we can re-arrange the previous equation to find the velocity of the car:
v= \sqrt{a_c r}= \sqrt{(15.625 m/s^2)(40 m)}=25 m/s
8 0
3 years ago
A rocket ship is accelerating at 200 m/s2, its mas is 135,000,000 kg. What is the force generated by this acceleration?
Rina8888 [55]

Acceleration does NOT "generate" force.  Acceleration NEEDS force to make it happen.  Without force ... provided by something else ... acceleration can't happen.

The force NEEDED to accelerate a mass with a certain acceleration is

Force needed = (mass) times (acceleration)

For the rocket ship in the question,

Force = (135,000,000 kg) times (200 m/s²)

Force = (135,000,000 x 200) kg-m/s²

<em>Force = 27 Giga-Newtons  </em>(27,000,000,000 Newtons)


The gas-generator cycle F-1 rocket engine, developed in the US by Rocketdyne in the late 1950s, was used in the Saturn V rocket, the main launch vehicle of NASA's Apollo moon lander program .  Five F-1 engines were used in the first stage of each Saturn V.  

==> The thrust of each F-1 engine at full throttle is 7,770 kilo-Newtons.  

It would take <em>3,475 </em>of these F-1 rocket engines, running full-throttle, to provide the force calculated in the answer to this question.  If you didn't have 3,475 F-1 rocket engines, then you couldn't accelerate 135,000,000 kg at 200 m/s².

(And by the way ... the mass of each F-1 engine is 8,400 kg.  So 3,475 engines alone account for 22% of the mass you're trying to accelerate.  And don't even get me started about the mass of the FUEL you'd need to carry.)

5 0
3 years ago
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