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3 years ago

if the earth were to cease rotating about its axis,then what is the increase in the value of gravity?

1 answer:

3 0

There is no adjustment in gravity, yet there is an adjustment in 'weightness'.
Gravitational compel and weight with respect to an edge are not similar things, despite the fact that it is normally educated something else.
Weight is really the aggregate of gravitational powers and of inertial drive for a question very still (no Coriolis compel) in a given casing.
In the event that the Earth were not pivoting, weight would increment most at the Equator and be unaltered at the Poles.

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A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00×10^4 N. how much w

erma4kov [3.2K]

<h3><u>Answer;</u></h3>

a) 5.00 x 10^8 J

<h3><u>Explanation;</u></h3>

The work done to move the sailboat is calculated through the equation;

W = F x d

where F is force and d is the distance.

Substituting the known values from the given above,

W = (5.00 x 10⁴ N)(10 km)(1000 m/ 1km)

= 5.00 x 10⁸ J

Thus, the work done is <u>5.00 x 10⁸Joules</u>

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3 years ago

Express force in terms of base units

MariettaO [177]

<h2><u>Answer:</u></h2>

<u></u>

<u>Force = kgm/s² ⟶ Newton</u>

<h2><u>Explanation:</u></h2>

<u></u>

According to the formula we've learnt,

Force = mass × acceleration.

To find force in terms of base units, we must first identify the base SI units of mass & acceleration.

Base SI unit of mass = kg (kilogram)

Base SI unit of acceleration = m/s² (meter per second squared)

So, the base unit of force is,

Force = mass × acceleration.

Force = kg × m/s²

<u>Force = kgm/s² ⟶ Newton</u>

________________

Hope it helps!

$\mathfrak{Lucazz}$

4 0

2 years ago

A container is ﬁlled with water to a depth of 26.2 cm. On top of the water ﬂoats a 16.1 cm thick layer of oil with a density of

Solnce55 [7]

Answer:

1.34 x 10^3 Pa

Explanation:

density of oil = 0.85 x 10^3 kg/m^3

g = 9.81 m/s^2

height of oil column = 16.1 cm = 0.161 m

Pressure on the surface of water = height of oil column x density of oil x g

= 0.161 x 0.85 x 10^3 x 9.81 = 1.34 x 10^3 Pa

Thus, the pressure on the surface of water is 1.34 x 10^3 Pa.

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3 years ago

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tigry1 [53]

Circuit board stuff

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3 years ago

Read 2 more answers

Why is weathering slow in cold, dry places?

Alexxandr [17]

Rate of weathering depends on temperature and moisture. Cold dry places have less water to weather things

Hope this helped!

Don't forget: Mark Brainliest!

Have a good day :)

6 0

3 years ago