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olchik [2.2K]
3 years ago
13

if the earth were to cease rotating about its axis,then what is the increase in the value of gravity?

Physics
1 answer:
IrinaK [193]3 years ago
3 0
There is no adjustment in gravity, yet there is an adjustment in 'weightness'. 
Gravitational compel and weight with respect to an edge are not similar things, despite the fact that it is normally educated something else. 
Weight is really the aggregate of gravitational powers and of inertial drive for a question very still (no Coriolis compel) in a given casing. 
In the event that the Earth were not pivoting, weight would increment most at the Equator and be unaltered at the Poles.
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Interactive LearningWare 10.1 reviews the concepts involved in this problem. A spring stretches by 0.0161 m when a 3.74-kg objec
yKpoI14uk [10]

Answer:

m = 3.91 kg

Explanation:

Given that,

Mass of the object, m = 3.74 kg

Stretching in the spring, x = 0.0161 m

The frequency of vibration, f = 3.84 Hz

When the object is suspended, the gravitational force is balanced by the spring force as :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{3.74\times 9.8}{0.0161}

k = 2276.52 N/m

The frequency of vibration is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2f^2}

m=\dfrac{2276.52}{4\pi^2\times (3.84)^2}

m = 3.91 kg

So, the mass of the object is 3.91 kg. Hence, this is the required solution.

8 0
3 years ago
Water (2510 g ) is heated until it just begins to boil. if the water absorbs 5.01×105 j of heat in the process, what was the ini
natka813 [3]
E=energy=5.09x10^5J = 509KJ 
<span>M=mass=2250g=2.25Kg </span>
<span>C=specific heat capacity of water= 4.18KJ/Kg </span>
<span>ΔT= change in temp= ? </span>
<span>E=mcΔT </span>
<span>509=(2.25)x(4.18)xΔT </span>
<span>509=9.405ΔT </span>
<span>ΔT=509/9.405=54.1degrees </span>
<span>Initial temp = 100-54 = 46 degrees </span>
<span>Hope this helps :)</span>
5 0
3 years ago
I NEED HELP ASAP
zzz [600]

Answer:

I believe the answer is C

Explanation:

because centripetal force is generally assosiated with rotation and how fast something spins

3 0
3 years ago
A gardener pushes a wheelbarrow around the edges of a lawn. When she has finished, she is 5 m from her starting point. She has t
zvonat [6]

Answer:

Work done by the gardner is 500 J

Explanation:

As we know that the gardner apply force perpendicular upward by magnitude 300 N and along the floor horizontal force is 100 N

so we have

F = 100 \hat i + 300 \hat j

now the displacement of the gardner along the floor is

d = 5\hat i

now work done is given as

W = F. d

so we have

W = (100 \hat i + 300 \hat j). (5\hat i)

W = 500 J

3 0
3 years ago
4. A hiker leaves camp and using a compass walks 4 km East, 6 km South, 3 km East, 5 km North, 10 km West, 8 km North and 3 km S
PSYCHO15rus [73]

Answer:

Because the hiker walked directly west and then directly north the two legs of the hike forms a right triangle. Therefore we can use the Pythagorean Theorem to solve this problem.

 

c=5

The hiker is 5km from camp and should head in a generally south-east direction

7 0
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