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Sindrei [870]
4 years ago
14

Is 6 1/4 -2 3/4 =4 2/4 explain

Mathematics
1 answer:
sineoko [7]4 years ago
3 0

Answer:

no its  3 and 1/2

Step-by-step explanation:

=6+1/4 − 2−3/4

6 − 2 = 4

1/4−3/4= negative 2/4

negative 2/4 =  negative 1/2

4 − 1/2  

= 3 1/2

Hope this helped :D

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So how do you do inverse fractions again?
agasfer [191]

Answer:

Opposite reciprocal; so 2/3 would be -3/2

Step-by-step explanation:

4 0
3 years ago
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You spend $30.40 on 4 CDs. Each CD costs the same amount and is on sale for 80% of the original price.
gizmo_the_mogwai [7]
Answer: The original price is $9.5
In this question, you are given the total spending( $30.40), amount of spend (4CDs) and the discounted price(80%). Then to find the original price of the CD, the calculation would be:

Total spending = amount of cd x CD discounted price
$30.40 = 4 x 0.8 Original price
3.2 Original price= $30.40
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4 0
3 years ago
Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver
umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) x^{2} + y^{2} + 4\cdot x - 6\cdot y  - 36 = 0 Given

(ii) x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0 Commutative Property

(iii) (x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0 Modulative/Associative Property/Additive Inverse Existence

(iv) (x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0  Perfect Trinomial Square

(v) (x+2)^{2} +(y-3)^{2} = 4 + 9 + 36 Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) (x+2)^{2} + (y-3)^{2} = 49 Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

(x-h)^{2}+ (y-k)^{2} = r^{2}

Where r is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

5 0
3 years ago
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What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
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\int \:-\frac{4}{y^2-8y}dy=\int \:dt
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y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

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3 years ago
Which of the following points are solutions to the inequality below?
Yakvenalex [24]
So, in order to find out which ordered pairs are the solutions to the given inequality above, we just have to plug in the given values.
Lets take option A.
2 > -3(0) + 2
2 > 0 + 2
2 > 2 ---- 2 is not greater than 2, which makes this ordered pair not a solution to the given inequality.
So, do the same with the rest of the ordered pairs.
So the ordered pairs that are the solutions would only be options C, E and F. Hope that answer helps. 
5 0
3 years ago
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