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gizmo_the_mogwai [7]
3 years ago
9

What is the product of two odd numbers and a multiple of 2

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0

An odd number is (2x) + 1

An even number is (2x)

These are the definitions.

Using the binomial (2x + 1)(2x + 1), we can see the properties of all products made from odd numbers.

Foiling will give 4x^2 + 4x + 1.

4x^2 is even because 4x^2 can be expressed as 2(2x) x 2(2x).

4x is even because 4x can be expressed as 2(2x)

This means that 4x^2 + 4x is even so the expression 4x^2 + 4x + 1 is odd because an even number + 1 is odd as shown by (2x) + 1.

This shows that every outcome of the product of 2 odd numbers will result being odd.

This means there is no answer to this problem, because any number that is a multiple of 2 is even. (Basically the definition of even)

ASHA 777 [7]3 years ago
5 0
Answer: a number

Explanation: choose the odd numbers and I’ll answer but right now how bout you ask my hood friend google
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\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &
\begin{array}{llll}
485\cdot 12\\
\underline{5280}
\end{array}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{a year, thus once}
\end{array}\to &1\\

t=years\to &4
\end{cases}
\\\\\\


\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot  4}-1}{\frac{0.06}{1}} \right]

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