9514 1404 393
Answer:
(3, 0)
Step-by-step explanation:
The line through these points intersects the x-axis at x=3.
The x-intercept is (3, 0).
_____
The x-intercept can be computed from ...
x-intercept = x1 -y1(x2 -x1)/(y2 -y1)
= -3 -(-4)(6-(-3))/(2-(-4)) = -3 +4(9/6) = -3 +6
x-intercept = 3
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Here, it is simple enough to plot the points and see where the line crosses the x-axis.
heres a key for then
SIN= O/H
COS= A/H
TAN= O/A
CSC= H/O
SEC= H/A
COT= A/O
let me know if u have anymore questions
Answer:
3/5 is ur answer
Step-by-step explanation:
ok so its SIN
SIN is o/h (o= opposite and h= hypotenuse)
so we can look at the picture and it says find the SIN of a
ok so the O would be 3 and the H would be 5
so ur answer would be 3/5
9514 1404 393
Answer:
1 1/5
Step-by-step explanation:
We want to find the number of times (5/6) goes into 1, so we divide ...
1/(5/6) = 1 × 6/5 = 6/5 = 1 1/5
There are 1 1/5 groups of 5/6 in 1.
_____
<em>Another way to look at it</em>
You can consider 1 to be divided into 6 equal part:
o o o o o o
We can group these in groups of 5, so each group is 5/6 of the whole:
(o o o o o) o
What we see is that we have 1 group, and 1/5 of another group.
That is, 1 has 1 1/5 groups of 5/6 in it.
Using the Pythagorean theorem we get:
![y^2+8^2=12^2.](https://tex.z-dn.net/?f=y%5E2%2B8%5E2%3D12%5E2.)
Simplifying the above result we get:
![y^2+64=144.](https://tex.z-dn.net/?f=y%5E2%2B64%3D144.)
Subtracting 64 from the above equation we get:
![\begin{gathered} y^2+64-64=144-64, \\ y^2=80. \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%5E2%2B64-64%3D144-64%2C%20%5C%5C%20y%5E2%3D80.%20%5Cend%7Bgathered%7D)
Therefore:
![y=\sqrt{80}\approx8.9.](https://tex.z-dn.net/?f=y%3D%5Csqrt%7B80%7D%5Capprox8.9.)
Answer:
Answer:
19
Step-by-step explanation:
- (n+7)/13 = 2 [given]
- n+7=26 [multiply both sides by 13]
- n=19 [subtract 7 from both sides]