FIRST ONE TO ANSWER GETS A BRAINLY!!! PLEASE HELP!!!

While completing a multiplication problem I need to know how to do it by associative

Vera_Pavlovna [14]

Associative property Says that you can add or multiply regardless of how the numbers are group

3 0

4 years ago

Mrs. Gilus is in charge of the budget for the school. Last year, we began the year with &708.88 in our bank account, but by

liberstina [14]

It sounds like they had $708.88 at the beginning, however by the end of the year they OWED $347.99. The first number is in the positive while the other is a negative. Add the last number to the first number for the amount that they have spent which would be $1,056.87.

8 0

3 years ago

A 40 inch board is to be cut into three pieces so that the second price is 4times as long as the first piece and the third piece

Anastasy [175]

Answer:

Step-by-step explanation:

Givens

Let the first piece be x

Let the second piece 4x

Let the third piece = 5x

Total length = 40 inches.

Equation

x + 4x + 5x = 40 Combine

Solution

10x = 40 Divide by 10

10x/10 = 40/10

x = 4

Answer

The smallest piece (x) = 4

The middle piece 4x = 4*4 = 16

The largest piece 5x= 5 * 4 = 20

3 0

1 year ago

Simplify your answer

Lelechka [254]

Answer:

Step-by-step explanation:

If 2u-6=4, let's solve for u.

Add 6 to both sides

2u-6+6 = 4+6

Simplify

2u = 10

Divide both sides by 2

u = 5

Now, we can solve u-5

5-5 = 0

8 0

2 years ago

Read 2 more answers

Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given $f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y$

a)

we know that $\int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1$

therefore $\int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1$

on integrating we get

c=(1/6640)

b)

$P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy$

on doing the integration we get

=0.37349

c)

marginal density of X is

$f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy$

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

$f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx$

on doing integration we get

$f(y)=\frac{(y+40.5)}{83}$

d)

$P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy$

solve the above integration we get the answer

e)

$P(X>20, 0$

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0

3 years ago