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PIT_PIT [208]
3 years ago
10

(06.02 mc) the equation of line cd is y=3x-3. Write an equation of a line perpendicular to line cd in slope intercept form that

contains points 3,1
Mathematics
2 answers:
Fynjy0 [20]3 years ago
6 0

Answer:

y = - \frac{1}{3} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - \frac{1}{3} x + 2 ← equation of perpendicular line

Veronika [31]3 years ago
6 0

Answer:

y = -1/3x + 2

got it correct on my test

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Okay, the first step is to rewrite this equation in "vertex form." You can search that up but it's basically just (h/k).

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