Given:
Required:
To calculate reference angle
Explanation:
Required answer:
Option B
J=UC solve for c please
1 answer:
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Answer:
60°
Step-by-step explanation:
Given :
DAB= (180 – 3x) °,
mZ B= (6x – 40) °, and
m ZC = (x+20) °.
DAB = mZ B + m ZC ( the exterior angle equal the sum of the two opposite interior angles)
180 - 3x = (6x - 40) + (x + 20)
180 - 3x = 6x - 40 + x + 20
180 - 3x = 6x + x - 40 + 20
180 - 3x = 7x - 20
180 + 20 = 7x + 3x
200 = 10x
x = 200/10
x = 20
Angle B = 6x - 40 = 6(20) - 40 = 120 - 40 = 80
Angle C = x + 20 = 20 + 20 = 40
BAC = 180 - (80 + 40) (SUM OF ANGLES IN A TRIANGLE)
BAC = 180 - 120
BAC = 60°
The probability that a pregnancy last at least 300 days is 0.01659
Step-by-step explanation:
The formula of z-score is z = (x - μ)/σ, where
- μ is the mean
- σ is the standard deviation
- x is the score
The lengths of human pregnancies are normally distributed with a
mean of 268 day & a standard deviation of 15 days
∴ μ = 268 days
∴ σ = 15 days
We need to find the probability that a pregnancy last at least 300 days
∵ At least means greater than or equal
∴ x ≥ 300 days
For probability that x ≥ 300 find the z-score and use the normal
distribution table to find the area to the right of the z-score
∵ z = (x - μ)/σ
∴
∴ <em>z</em> = 2.13
By using the normal distribution table of z-score
∵ The area (to the left of z-score) corresponding to z-score of 2.13
is 0.98341
∵ We need the area to the right of z-score
∴ P(x ≥ 300) = 1 - 0.98341
∴ P(x ≥ 300) = 0.01659
The probability that a pregnancy last at least 300 days is 0.01659
Learn more:
You can learn more about probability in brainly.com/question/9178881
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