Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Answer:
dependent variable -- As it depends on the other variables, changes when they change
Answer:D) peek
Explanation:Peek operation or function is the method that is used for the returning of the values on the front of the queue or stack type datatypes. This operation function over those datatypes having group or collection of the elements and does not eliminate any element from the queue.
NOsuchElemnet exception is shown when there is the peek operation in the queue for the element to be displayed on the top and no deletion can take place .Thus, the correct option is option(D).
Wiki is the correct answer
Answer:
First, medium: can see all the subject but maintain the focus in him
Second, close-up: To se the facial expressions and emotions
